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4-(2x+1)=4(2x+3)-x
We move all terms to the left:
4-(2x+1)-(4(2x+3)-x)=0
We get rid of parentheses
-2x-(4(2x+3)-x)-1+4=0
We calculate terms in parentheses: -(4(2x+3)-x), so:We add all the numbers together, and all the variables
4(2x+3)-x
We add all the numbers together, and all the variables
-1x+4(2x+3)
We multiply parentheses
-1x+8x+12
We add all the numbers together, and all the variables
7x+12
Back to the equation:
-(7x+12)
-2x-(7x+12)+3=0
We get rid of parentheses
-2x-7x-12+3=0
We add all the numbers together, and all the variables
-9x-9=0
We move all terms containing x to the left, all other terms to the right
-9x=9
x=9/-9
x=-1
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