4-((x-2)/4)=x-5

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Solution for 4-((x-2)/4)=x-5 equation: 



4-((x-2)/4)=x-5

We move all terms to the left:

4-((x-2)/4)-(x-5)=0

We get rid of parentheses

-((x-2)/4)-x+5+4=0

We multiply all the terms by the denominator


-((x-2)-x*4)+5*4)+4*4)=0



We calculate terms in parentheses: -((x-2)-x*4), so:

(x-2)-x*4

Wy multiply elements

(x-2)-4x

We get rid of parentheses

x-4x-2

We add all the numbers together, and all the variables

-3x-2

Back to the equation:

-(-3x-2)



We add all the numbers together, and all the variables

-(-3x-2)=0

We get rid of parentheses

3x+2=0

We move all terms containing x to the left, all other terms to the right

3x=-2

x=-2/3

x=-2/3

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