4+y/2=5/y-2

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Solution for 4+y/2=5/y-2 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

y/2+4 = 5/y-2 // - 5/y-2

y/2-(5/y)+2+4 = 0

y/2-5*y^-1+2+4 = 0

1/2*y^1-5*y^-1+6*y^0 = 0

(1/2*y^2+6*y^1-5*y^0)/(y^1) = 0 // * y^2

y^1*(1/2*y^2+6*y^1-5*y^0) = 0

y^1

(1/2)*y^2+6*y-5 = 0

(1/2)*y^2+6*y-5 = 0

DELTA = 6^2-(-5*4*(1/2))

DELTA = 46

DELTA > 0

y = (46^(1/2)-6)/(2*(1/2)) or y = (-46^(1/2)-6)/(2*(1/2))

y = 46^(1/2)-6 or y = -(46^(1/2)+6)

y in { -(46^(1/2)+6), 46^(1/2)-6} 

y in { -(46^(1/2)+6), 46^(1/2)-6 }

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