4+m=2(m+1)

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Solution for 4+m=2(m+1) equation: 



4+m=2(m+1)

We move all terms to the left:

4+m-(2(m+1))=0



We calculate terms in parentheses: -(2(m+1)), so:

2(m+1)

We multiply parentheses

2m+2

Back to the equation:

-(2m+2)



We get rid of parentheses

m-2m-2+4=0

We add all the numbers together, and all the variables

-1m+2=0

We move all terms containing m to the left, all other terms to the right

-m=-2

m=-2/-1

m=+2

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