4+c=3c-2(c+6)

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Solution for 4+c=3c-2(c+6) equation: 



4+c=3c-2(c+6)

We move all terms to the left:

4+c-(3c-2(c+6))=0



We calculate terms in parentheses: -(3c-2(c+6)), so:

3c-2(c+6)

We multiply parentheses

3c-2c-12

We add all the numbers together, and all the variables

c-12

Back to the equation:

-(c-12)



We get rid of parentheses

c-c+12+4=0

We add all the numbers together, and all the variables

16!=0

There is no solution for this equation

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