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4+X+17-2/3X=16
We move all terms to the left:
4+X+17-2/3X-(16)=0
Domain of the equation: 3X!=0We add all the numbers together, and all the variables
X!=0/3
X!=0
X∈R
X-2/3X+5=0
We multiply all the terms by the denominator
X*3X+5*3X-2=0
Wy multiply elements
3X^2+15X-2=0
a = 3; b = 15; c = -2;
Δ = b2-4ac
Δ = 152-4·3·(-2)
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{249}}{2*3}=\frac{-15-\sqrt{249}}{6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{249}}{2*3}=\frac{-15+\sqrt{249}}{6} $
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