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4+5x=24/x
We move all terms to the left:
4+5x-(24/x)=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
5x-(+24/x)+4=0
We get rid of parentheses
5x-24/x+4=0
We multiply all the terms by the denominator
5x*x+4*x-24=0
We add all the numbers together, and all the variables
4x+5x*x-24=0
Wy multiply elements
5x^2+4x-24=0
a = 5; b = 4; c = -24;
Δ = b2-4ac
Δ = 42-4·5·(-24)
Δ = 496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{496}=\sqrt{16*31}=\sqrt{16}*\sqrt{31}=4\sqrt{31}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{31}}{2*5}=\frac{-4-4\sqrt{31}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{31}}{2*5}=\frac{-4+4\sqrt{31}}{10} $
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