4+5x-7=3/4(12x-4)-4x

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Solution for 4+5x-7=3/4(12x-4)-4x equation: 



4+5x-7=3/4(12x-4)-4x

We move all terms to the left:

4+5x-7-(3/4(12x-4)-4x)=0



Domain of the equation: 4(12x-4)-4x)!=0

x∈R



We add all the numbers together, and all the variables

5x-(3/4(12x-4)-4x)-3=0

We multiply all the terms by the denominator


5x*4(12x-4)-4x)-(3-3*4(12x-4)-4x)=0

Wy multiply elements

20x^2(1-4x)-(3-12x(1-4x)=0



We calculate terms in parentheses: -(3-12x(1-4x), so:

3-12x(1-4x

determiningTheFunctionDomain
-12x(1-4x+3

Back to the equation:

-(-12x(1-4x+3)



We add all the numbers together, and all the variables

20x^2(-4x+1)-(-12x(-4x+4)=0



We calculate terms in parentheses: -(-12x(-4x+4), so:

-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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-12x(-4x+4





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