4+4z=6(2z+4)

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Solution for 4+4z=6(2z+4) equation: 



4+4z=6(2z+4)

We move all terms to the left:

4+4z-(6(2z+4))=0



We calculate terms in parentheses: -(6(2z+4)), so:

6(2z+4)

We multiply parentheses

12z+24

Back to the equation:

-(12z+24)



We get rid of parentheses

4z-12z-24+4=0

We add all the numbers together, and all the variables

-8z-20=0

We move all terms containing z to the left, all other terms to the right

-8z=20

z=20/-8

z=-2+1/2

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