4+3x+4(2x-3)=3x+4+2(2x+4)

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Solution for 4+3x+4(2x-3)=3x+4+2(2x+4) equation: 



4+3x+4(2x-3)=3x+4+2(2x+4)

We move all terms to the left:

4+3x+4(2x-3)-(3x+4+2(2x+4))=0

We multiply parentheses

3x+8x-(3x+4+2(2x+4))-12+4=0



We calculate terms in parentheses: -(3x+4+2(2x+4)), so:

3x+4+2(2x+4)

determiningTheFunctionDomain
3x+2(2x+4)+4

We multiply parentheses

3x+4x+8+4

We add all the numbers together, and all the variables

7x+12

Back to the equation:

-(7x+12)



We add all the numbers together, and all the variables

11x-(7x+12)-8=0

We get rid of parentheses

11x-7x-12-8=0

We add all the numbers together, and all the variables

4x-20=0

We move all terms containing x to the left, all other terms to the right

4x=20

x=20/4

x=5

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