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4+3x+11=3(x+5)
We move all terms to the left:
4+3x+11-(3(x+5))=0
We add all the numbers together, and all the variables
3x-(3(x+5))+15=0
We calculate terms in parentheses: -(3(x+5)), so:We get rid of parentheses
3(x+5)
We multiply parentheses
3x+15
Back to the equation:
-(3x+15)
3x-3x-15+15=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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