4+3/4(x+2)=3/8(x+1)

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Solution for 4+3/4(x+2)=3/8(x+1) equation: 



4+3/4(x+2)=3/8(x+1)

We move all terms to the left:

4+3/4(x+2)-(3/8(x+1))=0



Domain of the equation: 4(x+2)!=0

x∈R





Domain of the equation: 8(x+1))!=0

x∈R



We calculate fractions


(24xx/(4(x+2)*8(x+1)))+(-12xx/(4(x+2)*8(x+1)))+4=0



We calculate terms in parentheses: +(24xx/(4(x+2)*8(x+1))), so:

24xx/(4(x+2)*8(x+1))

We multiply all the terms by the denominator


24xx

Back to the equation:

+(24xx)





We calculate terms in parentheses: +(-12xx/(4(x+2)*8(x+1))), so:

-12xx/(4(x+2)*8(x+1))

We multiply all the terms by the denominator


-12xx

Back to the equation:

+(-12xx)



We get rid of parentheses

24xx-12xx+4=0

We move all terms containing x to the left, all other terms to the right

24xx-12xx=-4

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