4+3(x-2)+4x=5-3(x+4)

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Solution for 4+3(x-2)+4x=5-3(x+4) equation:



4+3(x-2)+4x=5-3(x+4)
We move all terms to the left:
4+3(x-2)+4x-(5-3(x+4))=0
We add all the numbers together, and all the variables
4x+3(x-2)-(5-3(x+4))+4=0
We multiply parentheses
4x+3x-(5-3(x+4))-6+4=0
We calculate terms in parentheses: -(5-3(x+4)), so:
5-3(x+4)
determiningTheFunctionDomain -3(x+4)+5
We multiply parentheses
-3x-12+5
We add all the numbers together, and all the variables
-3x-7
Back to the equation:
-(-3x-7)
We add all the numbers together, and all the variables
7x-(-3x-7)-2=0
We get rid of parentheses
7x+3x+7-2=0
We add all the numbers together, and all the variables
10x+5=0
We move all terms containing x to the left, all other terms to the right
10x=-5
x=-5/10
x=-1/2

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