4+3(x+2)=2-2(x-4)+5x

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Solution for 4+3(x+2)=2-2(x-4)+5x equation: 



4+3(x+2)=2-2(x-4)+5x

We move all terms to the left:

4+3(x+2)-(2-2(x-4)+5x)=0

We multiply parentheses

3x-(2-2(x-4)+5x)+6+4=0



We calculate terms in parentheses: -(2-2(x-4)+5x), so:

2-2(x-4)+5x

determiningTheFunctionDomain
-2(x-4)+5x+2

We add all the numbers together, and all the variables

5x-2(x-4)+2

We multiply parentheses

5x-2x+8+2

We add all the numbers together, and all the variables

3x+10

Back to the equation:

-(3x+10)



We add all the numbers together, and all the variables

3x-(3x+10)+10=0

We get rid of parentheses

3x-3x-10+10=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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