4+3(7+4x2)-100=x

Solution for 4+3(7+4x2)-100=x equation:

4+3(7+4x^2)-100=x

We move all terms to the left:

4+3(7+4x^2)-100-(x)=0

We add all the numbers together, and all the variables

3(7+4x^2)-1x-96=0

We multiply parentheses

12x^2-1x+21-96=0

We add all the numbers together, and all the variables

12x^2-1x-75=0

a = 12; b = -1; c = -75;
Δ = b2-4ac
Δ = -12-4·12·(-75)
Δ = 3601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{3601}}{2*12}=\frac{1-\sqrt{3601}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{3601}}{2*12}=\frac{1+\sqrt{3601}}{24}
$