4+3(4x-8)=2(3x+1)+6x

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Solution for 4+3(4x-8)=2(3x+1)+6x equation:


Simplifying
4 + 3(4x + -8) = 2(3x + 1) + 6x

Reorder the terms:
4 + 3(-8 + 4x) = 2(3x + 1) + 6x
4 + (-8 * 3 + 4x * 3) = 2(3x + 1) + 6x
4 + (-24 + 12x) = 2(3x + 1) + 6x

Combine like terms: 4 + -24 = -20
-20 + 12x = 2(3x + 1) + 6x

Reorder the terms:
-20 + 12x = 2(1 + 3x) + 6x
-20 + 12x = (1 * 2 + 3x * 2) + 6x
-20 + 12x = (2 + 6x) + 6x

Combine like terms: 6x + 6x = 12x
-20 + 12x = 2 + 12x

Add '-12x' to each side of the equation.
-20 + 12x + -12x = 2 + 12x + -12x

Combine like terms: 12x + -12x = 0
-20 + 0 = 2 + 12x + -12x
-20 = 2 + 12x + -12x

Combine like terms: 12x + -12x = 0
-20 = 2 + 0
-20 = 2

Solving
-20 = 2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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