4+3(3y-2)=-2(2y-6)+4y

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Solution for 4+3(3y-2)=-2(2y-6)+4y equation: 



4+3(3y-2)=-2(2y-6)+4y

We move all terms to the left:

4+3(3y-2)-(-2(2y-6)+4y)=0

We multiply parentheses

9y-(-2(2y-6)+4y)-6+4=0



We calculate terms in parentheses: -(-2(2y-6)+4y), so:

-2(2y-6)+4y

We add all the numbers together, and all the variables

4y-2(2y-6)

We multiply parentheses

4y-4y+12

We add all the numbers together, and all the variables

12

Back to the equation:

-(12)



We add all the numbers together, and all the variables

9y-14=0

We move all terms containing y to the left, all other terms to the right

9y=14

y=14/9

y=1+5/9

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