4+3(2c-5)=25

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Solution for 4+3(2c-5)=25 equation: 



4+3(2c-5)=25

We move all terms to the left:

4+3(2c-5)-(25)=0

We add all the numbers together, and all the variables

3(2c-5)-21=0

We multiply parentheses

6c-15-21=0

We add all the numbers together, and all the variables

6c-36=0

We move all terms containing c to the left, all other terms to the right

6c=36

c=36/6

c=6

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