4+2y+3y=2(2y+5)

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Solution for 4+2y+3y=2(2y+5) equation: 



4+2y+3y=2(2y+5)

We move all terms to the left:

4+2y+3y-(2(2y+5))=0

We add all the numbers together, and all the variables

5y-(2(2y+5))+4=0



We calculate terms in parentheses: -(2(2y+5)), so:

2(2y+5)

We multiply parentheses

4y+10

Back to the equation:

-(4y+10)



We get rid of parentheses

5y-4y-10+4=0

We add all the numbers together, and all the variables

y-6=0

We move all terms containing y to the left, all other terms to the right

y=6

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