4+2x=10(3/2x-2)

Solution for 4+2x=10(3/2x-2) equation:

4+2x=10(3/2x-2)

We move all terms to the left:

4+2x-(10(3/2x-2))=0


Domain of the equation: 2x-2))!=0

x∈R


We multiply all the terms by the denominator


2x*2x+4*2x-2))-(10(3-2))=0

We add all the numbers together, and all the variables

2x*2x+4*2x-2))-(101)=0

We add all the numbers together, and all the variables

2x*2x+4*2x=0

Wy multiply elements

4x^2+8x=0

a = 4; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·4·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*4}=\frac{-16}{8}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*4}=\frac{0}{8}
=0
$