4+2p=10(3/5)p-2)

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Solution for 4+2p=10(3/5)p-2) equation: 



4+2p=10(3/5)p-2)

We move all terms to the left:

4+2p-(10(3/5)p-2))=0



Domain of the equation: 5)p-2))+4!=0

p!=0/1

p!=0

p∈R



We add all the numbers together, and all the variables

2p-(10(+3/5)p-2))+4=0

We multiply all the terms by the denominator


2p*5)p-2))+4-(10(+3=0

Wy multiply elements

10p^2=0

a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$p=\frac{-b}{2a}=\frac{0}{20}=0$

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