4+2b=5+(b+4)

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Solution for 4+2b=5+(b+4) equation: 



4+2b=5+(b+4)

We move all terms to the left:

4+2b-(5+(b+4))=0



We calculate terms in parentheses: -(5+(b+4)), so:

5+(b+4)

determiningTheFunctionDomain
(b+4)+5

We get rid of parentheses

b+4+5

We add all the numbers together, and all the variables

b+9

Back to the equation:

-(b+9)



We get rid of parentheses

2b-b-9+4=0

We add all the numbers together, and all the variables

b-5=0

We move all terms containing b to the left, all other terms to the right

b=5

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