4+2/3(p+1)=3+3/4(p+2)

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Solution for 4+2/3(p+1)=3+3/4(p+2) equation: 



4+2/3(p+1)=3+3/4(p+2)

We move all terms to the left:

4+2/3(p+1)-(3+3/4(p+2))=0



Domain of the equation: 3(p+1)!=0

p∈R





Domain of the equation: 4(p+2))!=0

p∈R



We calculate fractions


(8pp/(3(p+1)*4(p+2)))+(-9pp/(3(p+1)*4(p+2)))+4=0



We calculate terms in parentheses: +(8pp/(3(p+1)*4(p+2))), so:

8pp/(3(p+1)*4(p+2))

We multiply all the terms by the denominator


8pp

Back to the equation:

+(8pp)





We calculate terms in parentheses: +(-9pp/(3(p+1)*4(p+2))), so:

-9pp/(3(p+1)*4(p+2))

We multiply all the terms by the denominator


-9pp

Back to the equation:

+(-9pp)



We get rid of parentheses

8pp-9pp+4=0

We move all terms containing p to the left, all other terms to the right

8pp-9pp=-4

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