4+2(y+3y)=4(y-3)+2y

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Solution for 4+2(y+3y)=4(y-3)+2y equation: 



4+2(y+3y)=4(y-3)+2y

We move all terms to the left:

4+2(y+3y)-(4(y-3)+2y)=0

We add all the numbers together, and all the variables

2(+4y)-(4(y-3)+2y)+4=0

We multiply parentheses

8y-(4(y-3)+2y)+4=0



We calculate terms in parentheses: -(4(y-3)+2y), so:

4(y-3)+2y

We add all the numbers together, and all the variables

2y+4(y-3)

We multiply parentheses

2y+4y-12

We add all the numbers together, and all the variables

6y-12

Back to the equation:

-(6y-12)



We get rid of parentheses

8y-6y+12+4=0

We add all the numbers together, and all the variables

2y+16=0

We move all terms containing y to the left, all other terms to the right

2y=-16

y=-16/2

y=-8

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