4+2(b+3)+5b=36

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Solution for 4+2(b+3)+5b=36 equation: 



4+2(b+3)+5b=36

We move all terms to the left:

4+2(b+3)+5b-(36)=0

We add all the numbers together, and all the variables

5b+2(b+3)-32=0

We multiply parentheses

5b+2b+6-32=0

We add all the numbers together, and all the variables

7b-26=0

We move all terms containing b to the left, all other terms to the right

7b=26

b=26/7

b=3+5/7

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