4+2(8z-5)=5(8z-6)+24

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Solution for 4+2(8z-5)=5(8z-6)+24 equation: 



4+2(8z-5)=5(8z-6)+24

We move all terms to the left:

4+2(8z-5)-(5(8z-6)+24)=0

We multiply parentheses

16z-(5(8z-6)+24)-10+4=0



We calculate terms in parentheses: -(5(8z-6)+24), so:

5(8z-6)+24

We multiply parentheses

40z-30+24

We add all the numbers together, and all the variables

40z-6

Back to the equation:

-(40z-6)



We add all the numbers together, and all the variables

16z-(40z-6)-6=0

We get rid of parentheses

16z-40z+6-6=0

We add all the numbers together, and all the variables

-24z=0

z=0/-24

z=0

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