4+2(4v-9)=-2(3v-2)+6v

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Solution for 4+2(4v-9)=-2(3v-2)+6v equation:



4+2(4v-9)=-2(3v-2)+6v
We move all terms to the left:
4+2(4v-9)-(-2(3v-2)+6v)=0
We multiply parentheses
8v-(-2(3v-2)+6v)-18+4=0
We calculate terms in parentheses: -(-2(3v-2)+6v), so:
-2(3v-2)+6v
We add all the numbers together, and all the variables
6v-2(3v-2)
We multiply parentheses
6v-6v+4
We add all the numbers together, and all the variables
4
Back to the equation:
-(4)
We add all the numbers together, and all the variables
8v-18=0
We move all terms containing v to the left, all other terms to the right
8v=18
v=18/8
v=2+1/4

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