4+(y+4)=32

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Solution for 4+(y+4)=32 equation: 



4+(y+4)=32

We move all terms to the left:

4+(y+4)-(32)=0

We add all the numbers together, and all the variables

(y+4)-28=0

We get rid of parentheses

y+4-28=0

We add all the numbers together, and all the variables

y-24=0

We move all terms containing y to the left, all other terms to the right

y=24

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