4+(3x+2)-8=5(2x+3)+5

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Solution for 4+(3x+2)-8=5(2x+3)+5 equation: 



4+(3x+2)-8=5(2x+3)+5

We move all terms to the left:

4+(3x+2)-8-(5(2x+3)+5)=0

We add all the numbers together, and all the variables

(3x+2)-(5(2x+3)+5)-4=0

We get rid of parentheses

3x-(5(2x+3)+5)+2-4=0



We calculate terms in parentheses: -(5(2x+3)+5), so:

5(2x+3)+5

We multiply parentheses

10x+15+5

We add all the numbers together, and all the variables

10x+20

Back to the equation:

-(10x+20)



We add all the numbers together, and all the variables

3x-(10x+20)-2=0

We get rid of parentheses

3x-10x-20-2=0

We add all the numbers together, and all the variables

-7x-22=0

We move all terms containing x to the left, all other terms to the right

-7x=22

x=22/-7

x=-3+1/7

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