4+(2y-3)-5(2y-3)=0

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Solution for 4+(2y-3)-5(2y-3)=0 equation:


Simplifying
4 + (2y + -3) + -5(2y + -3) = 0

Reorder the terms:
4 + (-3 + 2y) + -5(2y + -3) = 0

Remove parenthesis around (-3 + 2y)
4 + -3 + 2y + -5(2y + -3) = 0

Reorder the terms:
4 + -3 + 2y + -5(-3 + 2y) = 0
4 + -3 + 2y + (-3 * -5 + 2y * -5) = 0
4 + -3 + 2y + (15 + -10y) = 0

Reorder the terms:
4 + -3 + 15 + 2y + -10y = 0

Combine like terms: 4 + -3 = 1
1 + 15 + 2y + -10y = 0

Combine like terms: 1 + 15 = 16
16 + 2y + -10y = 0

Combine like terms: 2y + -10y = -8y
16 + -8y = 0

Solving
16 + -8y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + -8y = 0 + -16

Combine like terms: 16 + -16 = 0
0 + -8y = 0 + -16
-8y = 0 + -16

Combine like terms: 0 + -16 = -16
-8y = -16

Divide each side by '-8'.
y = 2

Simplifying
y = 2

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