4*x+(-5/3)*x=0

Solution for 4*x+(-5/3)*x=0 equation:

4x+(-5/3)*x=0


Domain of the equation: 3)*x!=0

x!=0/1

x!=0

x∈R


We multiply parentheses

-5x^2+4x=0

a = -5; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-5)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-5}=\frac{-8}{-10}
=4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-5}=\frac{0}{-10}
=0
$