4*2(8-4)+(12-6)*2+(6-4)*3+22=v

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Solution for 4*2(8-4)+(12-6)*2+(6-4)*3+22=v equation:


4*2(8-4)+(12-6)*2+(6-4)*3+22=v

We simplify the equation to the form, which is simple to understand 
4*2(8-4)+(12-6)*2+(6-4)*3+22=v

Reorder the terms in parentheses
+(+32)+(+6)*2+(+2)*3+22=v

Remove unnecessary parentheses
+32+(+6+)+*2+(+2+)+*3+22=+v

Reorder the terms in parentheses
+32+(+12)+(+2)*3+22=v

Remove unnecessary parentheses
+32+12+(+2+)+*3+22=+v

Reorder the terms in parentheses
+32+12+(+6)+22=v

Remove unnecessary parentheses
+32+12+6+22=+v

We move all terms containing v to the left and all other terms to the right. 
-1v=-32-12-6-22

We simplify left and right side of the equation. 
-1v=-72

We divide both sides of the equation by -01 to get v. 
v=72

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