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4(x-1)=3(x+2)-5
We move all terms to the left:
4(x-1)-(3(x+2)-5)=0
We multiply parentheses
4x-(3(x+2)-5)-4=0
We calculate terms in parentheses: -(3(x+2)-5), so:We get rid of parentheses
3(x+2)-5
We multiply parentheses
3x+6-5
We add all the numbers together, and all the variables
3x+1
Back to the equation:
-(3x+1)
4x-3x-1-4=0
We add all the numbers together, and all the variables
x-5=0
We move all terms containing x to the left, all other terms to the right
x=5
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