4*(b+2)*2-(3b-49)=0

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Solution for 4*(b+2)*2-(3b-49)=0 equation: 



4(b+2)*2-(3b-49)=0

We multiply parentheses

8b-(3b-49)+16=0

We get rid of parentheses

8b-3b+49+16=0

We add all the numbers together, and all the variables

5b+65=0

We move all terms containing b to the left, all other terms to the right

5b=-65

b=-65/5

b=-13

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