4*(0,2k-0,3)=1,3*(k-1/2)

Solution for 4*(0,2k-0,3)=1,3*(k-1/2) equation:

4(0.2k-0.3)=1.3(k-1/2)

We move all terms to the left:

4(0.2k-0.3)-(1.3(k-1/2))=0

We add all the numbers together, and all the variables

4(0.2k-0.3)-(1.3(+k-1/2))=0

We multiply parentheses

0k-(1.3(+k-1/2))-1.2=0

We multiply all the terms by the denominator


0k*2))-(1.3(+k-1-(1.2)*2))=0

We add all the numbers together, and all the variables

k+0k*2))-(1.3(=0

Wy multiply elements

0k^2+k=0

We add all the numbers together, and all the variables

k^2+k=0

a = 1; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·1·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*1}=\frac{-2}{2}
=-1
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*1}=\frac{0}{2}
=0
$