4(z-4)+12=7z+5

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Solution for 4(z-4)+12=7z+5 equation:


Simplifying
4(z + -4) + 12 = 7z + 5

Reorder the terms:
4(-4 + z) + 12 = 7z + 5
(-4 * 4 + z * 4) + 12 = 7z + 5
(-16 + 4z) + 12 = 7z + 5

Reorder the terms:
-16 + 12 + 4z = 7z + 5

Combine like terms: -16 + 12 = -4
-4 + 4z = 7z + 5

Reorder the terms:
-4 + 4z = 5 + 7z

Solving
-4 + 4z = 5 + 7z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-7z' to each side of the equation.
-4 + 4z + -7z = 5 + 7z + -7z

Combine like terms: 4z + -7z = -3z
-4 + -3z = 5 + 7z + -7z

Combine like terms: 7z + -7z = 0
-4 + -3z = 5 + 0
-4 + -3z = 5

Add '4' to each side of the equation.
-4 + 4 + -3z = 5 + 4

Combine like terms: -4 + 4 = 0
0 + -3z = 5 + 4
-3z = 5 + 4

Combine like terms: 5 + 4 = 9
-3z = 9

Divide each side by '-3'.
z = -3

Simplifying
z = -3

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