4(z-3)=2z/9+23

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Solution for 4(z-3)=2z/9+23 equation: 



4(z-3)=2z/9+23

We move all terms to the left:

4(z-3)-(2z/9+23)=0

We multiply parentheses

4z-(2z/9+23)-12=0

We get rid of parentheses

4z-2z/9-23-12=0

We multiply all the terms by the denominator


4z*9-2z-23*9-12*9=0

We add all the numbers together, and all the variables

-2z+4z*9-315=0

Wy multiply elements

-2z+36z-315=0

We add all the numbers together, and all the variables

34z-315=0

We move all terms containing z to the left, all other terms to the right

34z=315

z=315/34

z=9+9/34

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