4(z-3)=2(z+1)-3z

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Solution for 4(z-3)=2(z+1)-3z equation: 



4(z-3)=2(z+1)-3z

We move all terms to the left:

4(z-3)-(2(z+1)-3z)=0

We multiply parentheses

4z-(2(z+1)-3z)-12=0



We calculate terms in parentheses: -(2(z+1)-3z), so:

2(z+1)-3z

We add all the numbers together, and all the variables

-3z+2(z+1)

We multiply parentheses

-3z+2z+2

We add all the numbers together, and all the variables

-1z+2

Back to the equation:

-(-1z+2)



We get rid of parentheses

4z+1z-2-12=0

We add all the numbers together, and all the variables

5z-14=0

We move all terms containing z to the left, all other terms to the right

5z=14

z=14/5

z=2+4/5

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