4(z-3)=2(3z-5)

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Solution for 4(z-3)=2(3z-5) equation:


Simplifying
4(z + -3) = 2(3z + -5)

Reorder the terms:
4(-3 + z) = 2(3z + -5)
(-3 * 4 + z * 4) = 2(3z + -5)
(-12 + 4z) = 2(3z + -5)

Reorder the terms:
-12 + 4z = 2(-5 + 3z)
-12 + 4z = (-5 * 2 + 3z * 2)
-12 + 4z = (-10 + 6z)

Solving
-12 + 4z = -10 + 6z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-6z' to each side of the equation.
-12 + 4z + -6z = -10 + 6z + -6z

Combine like terms: 4z + -6z = -2z
-12 + -2z = -10 + 6z + -6z

Combine like terms: 6z + -6z = 0
-12 + -2z = -10 + 0
-12 + -2z = -10

Add '12' to each side of the equation.
-12 + 12 + -2z = -10 + 12

Combine like terms: -12 + 12 = 0
0 + -2z = -10 + 12
-2z = -10 + 12

Combine like terms: -10 + 12 = 2
-2z = 2

Divide each side by '-2'.
z = -1

Simplifying
z = -1

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