4(z-3)-z=4(z+1)+20

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Solution for 4(z-3)-z=4(z+1)+20 equation:


Simplifying
4(z + -3) + -1z = 4(z + 1) + 20

Reorder the terms:
4(-3 + z) + -1z = 4(z + 1) + 20
(-3 * 4 + z * 4) + -1z = 4(z + 1) + 20
(-12 + 4z) + -1z = 4(z + 1) + 20

Combine like terms: 4z + -1z = 3z
-12 + 3z = 4(z + 1) + 20

Reorder the terms:
-12 + 3z = 4(1 + z) + 20
-12 + 3z = (1 * 4 + z * 4) + 20
-12 + 3z = (4 + 4z) + 20

Reorder the terms:
-12 + 3z = 4 + 20 + 4z

Combine like terms: 4 + 20 = 24
-12 + 3z = 24 + 4z

Solving
-12 + 3z = 24 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-12 + 3z + -4z = 24 + 4z + -4z

Combine like terms: 3z + -4z = -1z
-12 + -1z = 24 + 4z + -4z

Combine like terms: 4z + -4z = 0
-12 + -1z = 24 + 0
-12 + -1z = 24

Add '12' to each side of the equation.
-12 + 12 + -1z = 24 + 12

Combine like terms: -12 + 12 = 0
0 + -1z = 24 + 12
-1z = 24 + 12

Combine like terms: 24 + 12 = 36
-1z = 36

Divide each side by '-1'.
z = -36

Simplifying
z = -36

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