4(z+5)=324(z+5)=32

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Solution for 4(z+5)=324(z+5)=32 equation: 



4(z+5)=324(z+5)=32

We move all terms to the left:

4(z+5)-(324(z+5))=0

We multiply parentheses

4z-(324(z+5))+20=0



We calculate terms in parentheses: -(324(z+5)), so:

324(z+5)

We multiply parentheses

324z+1620

Back to the equation:

-(324z+1620)



We get rid of parentheses

4z-324z-1620+20=0

We add all the numbers together, and all the variables

-320z-1600=0

We move all terms containing z to the left, all other terms to the right

-320z=1600

z=1600/-320

z=-5

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