4(z+4)=-2(z+1)

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Solution for 4(z+4)=-2(z+1) equation:



4(z+4)=-2(z+1)
We move all terms to the left:
4(z+4)-(-2(z+1))=0
We multiply parentheses
4z-(-2(z+1))+16=0
We calculate terms in parentheses: -(-2(z+1)), so:
-2(z+1)
We multiply parentheses
-2z-2
Back to the equation:
-(-2z-2)
We get rid of parentheses
4z+2z+2+16=0
We add all the numbers together, and all the variables
6z+18=0
We move all terms containing z to the left, all other terms to the right
6z=-18
z=-18/6
z=-3

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