4(z+4)-3(z+2)=11

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Solution for 4(z+4)-3(z+2)=11 equation: 


Simplifying
4(z + 4) + -3(z + 2) = 11

Reorder the terms:
4(4 + z) + -3(z + 2) = 11
(4 * 4 + z * 4) + -3(z + 2) = 11
(16 + 4z) + -3(z + 2) = 11

Reorder the terms:
16 + 4z + -3(2 + z) = 11
16 + 4z + (2 * -3 + z * -3) = 11
16 + 4z + (-6 + -3z) = 11

Reorder the terms:
16 + -6 + 4z + -3z = 11

Combine like terms: 16 + -6 = 10
10 + 4z + -3z = 11

Combine like terms: 4z + -3z = 1z
10 + 1z = 11

Solving
10 + 1z = 11

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + 1z = 11 + -10

Combine like terms: 10 + -10 = 0
0 + 1z = 11 + -10
1z = 11 + -10

Combine like terms: 11 + -10 = 1
1z = 1

Divide each side by '1'.
z = 1

Simplifying
z = 1

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