4(z+2)=2+40

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Solution for 4(z+2)=2+40 equation: 



4(z+2)=2+40

We move all terms to the left:

4(z+2)-(2+40)=0

We add all the numbers together, and all the variables

4(z+2)-42=0

We multiply parentheses

4z+8-42=0

We add all the numbers together, and all the variables

4z-34=0

We move all terms containing z to the left, all other terms to the right

4z=34

z=34/4

z=8+1/2

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