4(z+1)+3(3z+6)=36

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Solution for 4(z+1)+3(3z+6)=36 equation:


Simplifying
4(z + 1) + 3(3z + 6) = 36

Reorder the terms:
4(1 + z) + 3(3z + 6) = 36
(1 * 4 + z * 4) + 3(3z + 6) = 36
(4 + 4z) + 3(3z + 6) = 36

Reorder the terms:
4 + 4z + 3(6 + 3z) = 36
4 + 4z + (6 * 3 + 3z * 3) = 36
4 + 4z + (18 + 9z) = 36

Reorder the terms:
4 + 18 + 4z + 9z = 36

Combine like terms: 4 + 18 = 22
22 + 4z + 9z = 36

Combine like terms: 4z + 9z = 13z
22 + 13z = 36

Solving
22 + 13z = 36

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-22' to each side of the equation.
22 + -22 + 13z = 36 + -22

Combine like terms: 22 + -22 = 0
0 + 13z = 36 + -22
13z = 36 + -22

Combine like terms: 36 + -22 = 14
13z = 14

Divide each side by '13'.
z = 1.076923077

Simplifying
z = 1.076923077

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