4(y-6)+11y=21

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Solution for 4(y-6)+11y=21 equation: 



4(y-6)+11y=21

We move all terms to the left:

4(y-6)+11y-(21)=0

We add all the numbers together, and all the variables

11y+4(y-6)-21=0

We multiply parentheses

11y+4y-24-21=0

We add all the numbers together, and all the variables

15y-45=0

We move all terms containing y to the left, all other terms to the right

15y=45

y=45/15

y=3

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