4(y-5)+3=2(2y-3)

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Solution for 4(y-5)+3=2(2y-3) equation:


Simplifying
4(y + -5) + 3 = 2(2y + -3)

Reorder the terms:
4(-5 + y) + 3 = 2(2y + -3)
(-5 * 4 + y * 4) + 3 = 2(2y + -3)
(-20 + 4y) + 3 = 2(2y + -3)

Reorder the terms:
-20 + 3 + 4y = 2(2y + -3)

Combine like terms: -20 + 3 = -17
-17 + 4y = 2(2y + -3)

Reorder the terms:
-17 + 4y = 2(-3 + 2y)
-17 + 4y = (-3 * 2 + 2y * 2)
-17 + 4y = (-6 + 4y)

Add '-4y' to each side of the equation.
-17 + 4y + -4y = -6 + 4y + -4y

Combine like terms: 4y + -4y = 0
-17 + 0 = -6 + 4y + -4y
-17 = -6 + 4y + -4y

Combine like terms: 4y + -4y = 0
-17 = -6 + 0
-17 = -6

Solving
-17 = -6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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