4(y-4)+8(y+1)=52

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Solution for 4(y-4)+8(y+1)=52 equation: 


Simplifying
4(y + -4) + 8(y + 1) = 52

Reorder the terms:
4(-4 + y) + 8(y + 1) = 52
(-4 * 4 + y * 4) + 8(y + 1) = 52
(-16 + 4y) + 8(y + 1) = 52

Reorder the terms:
-16 + 4y + 8(1 + y) = 52
-16 + 4y + (1 * 8 + y * 8) = 52
-16 + 4y + (8 + 8y) = 52

Reorder the terms:
-16 + 8 + 4y + 8y = 52

Combine like terms: -16 + 8 = -8
-8 + 4y + 8y = 52

Combine like terms: 4y + 8y = 12y
-8 + 12y = 52

Solving
-8 + 12y = 52

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 12y = 52 + 8

Combine like terms: -8 + 8 = 0
0 + 12y = 52 + 8
12y = 52 + 8

Combine like terms: 52 + 8 = 60
12y = 60

Divide each side by '12'.
y = 5

Simplifying
y = 5

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