4(y-4)+3(y+3)=35

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Solution for 4(y-4)+3(y+3)=35 equation: 


Simplifying
4(y + -4) + 3(y + 3) = 35

Reorder the terms:
4(-4 + y) + 3(y + 3) = 35
(-4 * 4 + y * 4) + 3(y + 3) = 35
(-16 + 4y) + 3(y + 3) = 35

Reorder the terms:
-16 + 4y + 3(3 + y) = 35
-16 + 4y + (3 * 3 + y * 3) = 35
-16 + 4y + (9 + 3y) = 35

Reorder the terms:
-16 + 9 + 4y + 3y = 35

Combine like terms: -16 + 9 = -7
-7 + 4y + 3y = 35

Combine like terms: 4y + 3y = 7y
-7 + 7y = 35

Solving
-7 + 7y = 35

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + 7y = 35 + 7

Combine like terms: -7 + 7 = 0
0 + 7y = 35 + 7
7y = 35 + 7

Combine like terms: 35 + 7 = 42
7y = 42

Divide each side by '7'.
y = 6

Simplifying
y = 6

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