4(y-4)+3(y+1)=22

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Solution for 4(y-4)+3(y+1)=22 equation:


Simplifying
4(y + -4) + 3(y + 1) = 22

Reorder the terms:
4(-4 + y) + 3(y + 1) = 22
(-4 * 4 + y * 4) + 3(y + 1) = 22
(-16 + 4y) + 3(y + 1) = 22

Reorder the terms:
-16 + 4y + 3(1 + y) = 22
-16 + 4y + (1 * 3 + y * 3) = 22
-16 + 4y + (3 + 3y) = 22

Reorder the terms:
-16 + 3 + 4y + 3y = 22

Combine like terms: -16 + 3 = -13
-13 + 4y + 3y = 22

Combine like terms: 4y + 3y = 7y
-13 + 7y = 22

Solving
-13 + 7y = 22

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '13' to each side of the equation.
-13 + 13 + 7y = 22 + 13

Combine like terms: -13 + 13 = 0
0 + 7y = 22 + 13
7y = 22 + 13

Combine like terms: 22 + 13 = 35
7y = 35

Divide each side by '7'.
y = 5

Simplifying
y = 5

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